Ask Experts Questions for FREE Help !
Ask
    burgess87's Avatar
    burgess87 Posts: 40, Reputation: 2
    Junior Member
     
    #1

    Jul 8, 2014, 12:27 AM
    Logarithm problem
    Help needed to solve calculus problem

    If log 2 = 0.301, then what is the number of digits in 520 ?

    Please tell me the procedure to solve these kind of problems
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
    Expert
     
    #2

    Jul 8, 2014, 05:53 AM
    Start with the understanding that for any integer A, the number of digits is equal to log_10(A) rounded up to the next whole number. For example, the number of digits in the number 123456 is log_10(123456) = 5.09, which rounds up to 6. So for this problem the number of digits in 5^20 is log_10(5^20) rounded up. Since 5 = 10/2, you can use your log identities to determine log_10((10/2)^20). Can you take it from here?

Not your question? Ask your question View similar questions

 

Question Tools Search this Question
Search this Question:

Advanced Search

Add your answer here.


Check out some similar questions!

Another logarithm please help [ 1 Answers ]

Log3(xsquared 1)

Logarithm Problem [ 2 Answers ]

Solve the equation. log2 x^2 = log2 (3x + 18) Use natural logarithms to evaluate the logarithm to the nearest hundredth. log square root of 5, 31.2

How to solve logarithm [ 1 Answers ]

what is the constant in log2(x16y9) = Alogx +Blog2y such A=___ and the constant and B=__

Logarithm basics [ 1 Answers ]

Express as a single logarithm. Log(3)11+log(3)7 igot the answer log(3)18. Need help

Logarithm problem [ 2 Answers ]

Approximate: log a 16, given log a 2=.4307


View more questions Search