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    Jm720's Avatar
    Jm720 Posts: 1, Reputation: 1
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    #1

    Oct 14, 2013, 04:40 PM
    Finding the zeros of a quadratic function:
    Driving along a crowded freeway, you notice that it takes a time (t) to go from one mile marker to the next. When you increase your speed by 8.4 mi/hr, the time to go one mile decreases by 14 seconds. What was your original speed?
    ma0641's Avatar
    ma0641 Posts: 15,675, Reputation: 1012
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    #2

    Oct 14, 2013, 08:24 PM
    Show us your work and we will try to help. We do not do homework for you.
    Celine91's Avatar
    Celine91 Posts: 51, Reputation: 9
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    #3

    Oct 15, 2013, 12:47 AM
    For the first case: t1 = 1/v.. hr
    For the second case (speed increase): t2 = 1/(v+8.4)... hr

    The time difference is 14 sec = 14/3600 hr

    t1-t2 = 14/3600 hr
    1/v - 1/(v+8.4) = 14/3600 hr... Work with the left side fraction and then cross multiplication

    8.4*3600 = 14 * v * (v + 8.4)
    30240 = 14 * v * (v + 8.4)... Simplify again and use calculator to solve 2nd degree equation

    V = 42.465 mi /hr

    Good luck!
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