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    kan_21's Avatar
    kan_21 Posts: 1, Reputation: 1
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    #1

    Jul 23, 2013, 07:08 PM
    math
    What are the roots of this equation?

    x2 - 4x + 9 = 0
    1102568's Avatar
    1102568 Posts: 65, Reputation: -1
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    #2

    Jul 23, 2013, 07:14 PM
    x2 - 4x + 9 = 0



    x2 -4x = -9

    x-2x= -4.5

    -x=-4.5

    x=4.5

    It has been a while since I have done algebra, but I think this is the answer.
    Enigma1999's Avatar
    Enigma1999 Posts: 2,223, Reputation: 1077
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    #3

    Jul 23, 2013, 07:21 PM
    Quote Originally Posted by 1102568 View Post
    x2 - 4x + 9 = 0



    x2 -4x = -9

    x-2x= -4.5

    -x=-4.5

    x=4.5

    It has been a while since I have done algebra, but I think this is the answer.
    That is correct, but on this site we cannot do anyone's homework. We can help guide, but not give the answers.
    Alty's Avatar
    Alty Posts: 28,317, Reputation: 5972
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    #4

    Jul 24, 2013, 12:41 AM
    Please see our expectations for homework help, and the rules of this site:

    Ask Me Help Desk - Announcements in Forum : Homework Help
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #5

    Jul 24, 2013, 05:36 AM
    I suspect that the OP meant this:



    kan_21: use the quadratic formula to solve this. The roots turn out to be complex.
    neodarwinian's Avatar
    neodarwinian Posts: 74, Reputation: 1
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    #6

    Jul 24, 2013, 06:21 PM
    Using the discriminant,

    b^2 - 4ac

    One will see that the roots are unreal numbers; complex.

    You have already been advised to use the quadratic equation here.
    jamesjoseph11's Avatar
    jamesjoseph11 Posts: 4, Reputation: 1
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    #7

    Aug 27, 2013, 04:59 AM
    x^2 -4x+9 =0
    consider the formula, x = [-b ± √(b2 - 4ac)]/2a ------------(1)
    standard form of the equation is y=a(x^2)+bx+c
    from the equation, a = 1, b = -4, c=9
    substitute the values to the equation (1)
    consider the formula, x = [-b ± √(b2 - 4ac)]/2a
    This will help you in finding x.
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