[puneet190]

If a motor of 2.2 Kw which is running 24 hrs a day is replaced with 1.1 kwperforming same job of transferring the material through a screw conveyor, what will be the saving in terms of connecting load.

[stanfortyman]

Without knowing the kWh rates, and the actual load on the motor, it is impossible to say.
If the motor can do the same job you're saving 1100 watts for 24 hours. Thing is, if the 2.2kW motor was doing this job before it was most likely not working at full load.

[tkrussell]

Stan makes a good point, but assuming both motors are drawing nameplate watts, the difference is 1.1kW, and one hour is 1.1 kiloWatt-hour.

Even if the 2.2kW motor was not running at full load, the difference would be negligible.

Discover what you pay for energy for kWh times 1.1 kWh, and there is your cost of energy per hour.


Assuming $0.15 cents per kWh, the cost per hour would be $0.165, one full day would save $3.96.

[puneet190]

Stan makes a good point, but assuming both motors are drawing nameplate watts, the difference is 1.1kW, and one hour is 1.1 kiloWatt-hour.

Even if the 2.2kW motor was not running at full load, the difference would be negligible.

Discover what you pay for energy for kWh times 1.1 kWh, and there is your cost of energy per hour.


Assuming $0.15 cents per kWh, the cost per hour would be $0.165, one full day would save $3.96.

I know that but what's the concept of connecting load , suppose if I place a motor with 10 kw there instead of 2.2 kw then it will be drawing the same current then will it be wise to use 10 kw motor if motor buying cost is negligible.?

[tkrussell]

If you knew that why did you ask? And now you ask about a 10 kW motor, as if we were suppose to know what you meant?

A 10kW motor will not draw the same lower current of a 2 kw motor.

How do you come up with a 10 kw motor will draw the same as a 2?

Now your not making any sense.