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    esined123's Avatar
    esined123 Posts: 3, Reputation: 1
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    #1

    Oct 3, 2012, 05:05 PM
    solve math problems for free
    Melinda has nickels and dimes in her bank. She has four fewer nickels than quarters. She has $3.70 in the bank. How many coins of each type does she have. I need to know haw to set up the equation.
    esined123's Avatar
    esined123 Posts: 3, Reputation: 1
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    #2

    Oct 3, 2012, 05:10 PM
    x=nickels=0.05
    x-4x=four fewer nickels
    +4x=quarters-0.25

    x-4x+4x
    esined123's Avatar
    esined123 Posts: 3, Reputation: 1
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    #3

    Oct 3, 2012, 05:14 PM
    Are you going to help me solve the problem I just submitted?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Oct 4, 2012, 12:40 AM
    I would prefer if you change the way you attempted it a bit and retry.

    Let x be the number of nickels and y be the number of dimes.

    The net value of the nickels is 0.05x and the net value of the dimes is 0.1y

    That is: if you have 5 nickels, their value would be 0.05(5) = 0.25.

    I think that you meant dimes in the second sentence? Taking it as such, that means that y is greater than 4 by 4, or:
    x + 4 = y

    You need to add 4 to the nickels so that they equal the number of dimes.

    Their total value is:
    0.05x + 0.1y = 3.70

    Can you try again?

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