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    rzelka's Avatar
    rzelka Posts: 2, Reputation: 1
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    #1

    Sep 25, 2012, 07:55 AM
    how to solve 2(sin2x) - 2(sinx)
    how to solve 2(sin2x) - 2(sinx) ?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Sep 25, 2012, 08:51 AM
    This is not a complete question.

    And you haven't shown your attempt.
    rzelka's Avatar
    rzelka Posts: 2, Reputation: 1
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    #3

    Sep 25, 2012, 08:57 AM
    Because I do not know how to even start it.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Sep 25, 2012, 09:34 AM
    If you're being given such a question as homework, it means that you should be able to do it and that it's only practice. Review your notes, your books, there should be examples. Apply the same concept.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #5

    Sep 25, 2012, 10:54 AM
    You can't "solve" the equation as written - it needs an equal sign somewhere. Maybe you meant to write 2sin(2x)= 2sin(x), or perhaps 2sin(2x)-2sin(x) = 0?

    Here's a hint though: consider the identity for sin(2x) - substitute that in and it should simplify things nicely.

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