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    brittanylee00's Avatar
    brittanylee00 Posts: 1, Reputation: 1
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    #1

    Sep 21, 2012, 02:14 PM
    solve square root (2x-3)=5 showing all steps
    I need help on how to solve problems like that. Please show all steps.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Sep 22, 2012, 11:54 AM
    Post your attempt. Please show all calculations.
    RPVega's Avatar
    RPVega Posts: 29, Reputation: 2
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    #3

    Sep 25, 2012, 12:00 AM
    (2x-3)**(1/2)=5, where the two asterisks (**) denote raising (2x-3) to the (1/2) power. Recall that raising an expression to the 1/2 power is the same as taking
    the square root of the expression.

    Next, raise both sides of the equation to the power of 2. This will eliminate the
    square root radical sign on the left of the equals (=) sign, and the number 5 on
    the right side of the equals sign, raised to the power of 2, becomes 25. This is
    shown below:

    [(2x-3)**(1/2)]**2 = 5**2
    2x-3=25

    I'll leave it as an exercize for you to solve 2x-3=25 for x. (Hint: add 3 to BOTH
    sides of 2x-3=25, then divide BOTH sides of the resulting equation, 2x=28, by 2.)
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