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    qmaster Posts: 12, Reputation: 1
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    #1

    Aug 3, 2012, 05:56 AM
    One body is dropped and a second body is thrown downwards with an initial velocity of
    One body is dropped and a second body is thrown downwards with an initial velocity of 1m/s simultaneously. The separation between these two bodies is 18m after a time……………….. ans:18 sec
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Aug 3, 2012, 06:47 AM
    Yes, 18 seconds is correct.
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    qmaster Posts: 12, Reputation: 1
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    #3

    Aug 3, 2012, 08:21 PM
    Could you explain how?
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    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Aug 6, 2012, 05:39 AM
    Both have the same initial starting point and are subject to the same acceleration of -9.8m/s^2. The only difference is that one has a 1m/s initial velocity. That initial velocity times 18 seconds gives a distance of 18m due solely to the advantage of that 1m/s start.

    Mathematically you can see it from the equation:



    For two different objects that have the same value for x_0 and a, and one has initial velocity v_0 and the other has initial velocity 0, the difference between them is simply .

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