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physic · Apr 29, 2012, 02:33 AM

Only a few weeks ago I would challenge these theories based on the evidence we can find on social media.
"newton's universal gravitational constant actually is NOT constant"
newton's universal gravitational constant actually is NOT constant
Newton's Universal Gravitational Constant Actually is NOT Constant

according to explanation: "Estakhr's Constant $B=0.1292242606 \frac {N}{(\frac {Mev}{c^2})^2}$
is a kind of cosmic limits and suitable conversion factor that is able to transform units of mass square $m^2$ to units of force $F$ .

$F=m^2. B$ that is same $E=m.c^2$ then force of a photon will be $F=(\frac {E}{c^2})^2. B$ that is maximum force!

The amazing thing that rocked my world it is that this theory is able to unified all physical forces in one theory!
When you multiply $2\pi$ number by the Estakhr's constant $B$ . Estakhr's constant Will become Estakhr's Constant increased:
$\underline B=2\pi B=0.8119399752 \frac {Rad.N}{(\frac {Mev}{c^2})^2}$
in this theory planck's length $\ell_p$ and also Newton's Gravitational constant $G$ actually are not constant. For example planck's length is Estakhr's length when speed parameter is close to zero, but not zero:
$L_E=\lim_{\beta \to 0} R. \beta^{\frac {3}{2}}=\ell_e$
so Newton's Gravitation constant could not be constant and actually is Estakhr's Gravitation when speed parameter is close to zero but not zero:

$G_E=\lim_{\beta \to 0}\underline B. R^2.\beta^3=G_N$
Estakhr Gravitation is Floating between the two values of speed parameter $0 <\beta \le 1$
which means Newton's Universal Gravitational Constant, may not be a constant.
this is Estakhr's General Relation of Force:
$F_E=\underline B.\beta^3.m.M$
so Gravitational force will be Estakhr's General Relation of Force when the speed parameter is close to zero but not zero
$F_E=\lim_{\beta \to 0}\underline B.\beta^3.m.M \to F_G=\frac {G.m.M}{R^2}$
and the electrostatic force will be Estakhr's General Relation of Force when the speed parameter is close to fine structure constant $\alpha=\frac {1}{137}$ :
$F_E=\lim_{\beta \to \alpha=\frac {1}{137}}\underline B.\beta^3.m.M=\underline B. \alpha^3.m_e^2.\ \to F_e=\frac {e^2}{4\pi.\epsilon_0.a_0^2}$

now the question, is theory correct?
for example for F=1000N:
$\frac {E}{c^2}=\sqrt {\frac {F}{B}}=\sqrt {\frac {1000N}{B}}=88.0 \frac {Mev}{c^2}$

physic · May 2, 2012, 05:07 PM

According to Estakhr, Ahmad Reza (MG13 - Talk detail)Title: Newton's universal gravitational constant actually is NOT constant. when the Newtonian constant of gravitation $G=6.67384(80)×10^{-11}\,\frac {m3}<br /> {kg.s^2}$ is NOT constant which means not even Planck's Length is NOT constant and also all measurements with the source of gravitational constants are NOT constant
just like:

physic · May 10, 2012, 04:46 PM

$F_G=\frac {GmM}{R^2}\to F_E=\frac {(\lim_{\beta\to 0} \underline B.\beta^3.\cancel {R^2})mM}{\cancel {R^2}}=\lim_{\beta\to 0}\underline B \beta^3 mM$
this equation proof that Estakhr's Gravitational Force is correct!.