Ask Experts Questions for FREE Help !
Ask
    natardy's Avatar
    natardy Posts: 1, Reputation: 1
    New Member
    		  
    #1

    Apr 14, 2011, 09:16 AM
    show that 3x^2-y^2+xy=4 is equal to y=2x when the gradient of the tangent is 8/3
    Pure mathematics/module 1/implicit differntiation
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
    Ultra Member
    		  
    #2

    Apr 14, 2011, 10:25 AM

    Implicitly differentiate



    to get y'.

    Set the result = to 8/3 and solve for y.
    dvmohanrao's Avatar
    dvmohanrao Posts: 1, Reputation: 1
    New Member
    		  
    #3

    May 31, 2011, 06:59 PM
    3x^2-y^2+xy=4

    differentiate implicitly

    6x - 2y y ' + x y ' + y = 0

    y ' (2y - x) = 6x + y

    y ' = (6x + y)/(2y - x)

    since gradient is 8/3

    => (6x + y)/(2y - x) = 8/3

    => 18x + 3y = 16y - 8x

    => 13y = 26x

    => y = 2x
Not your question? Ask your question View similar questions
 

Question Tools Search this Question
Search this Question:

Advanced Search


Check out some similar questions!

Are W2's required to show NY State Wages equal to the Federal Wages? [ 3 Answers ]

For example and employee works and lives in NY and earns $80,000, then moves to Arizona and Earns $20,000. So his Federal Wages are $100,000. On the W2 it lists for Box 16 NY $100,000 and AZ $20,000. I am told that is because NY requires State Wages to equal Federal. Is that correct?

Gradient of Tangents Calculus [ 1 Answers ]

Find the gradient of the tangent to the curve y= square root x plus 8/square root x at the point (4,6)

How do I find a gradient with a equation? [ 1 Answers ]

I know how to find the gradient but the question gives a equation 2x - 5y = 18 how do I find x and y to draw a graph?

Gradient of tangent [ 1 Answers ]

Hi there, How would I solve this? A tangent to the hyperbola y=1/(2x) , x>0 cuts the y- axis at the point y=2 Find the gradient of this tangent? If I differentiate the hyperbola, I would get -1/(2x^2) and then I don't know how to go on about doing it. Thanks

View more questions Search