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    gryder's Avatar
    gryder Posts: 1, Reputation: 1
    New Member
     
    #1

    Apr 26, 2004, 10:09 PM
    Trig problem
    Can someone tell me how to solve for the angles of a triangle, when all three sides are known, but all angles are un-known..

    Any help appreciated.

    Don Gryder
    reinsuranc's Avatar
    reinsuranc Posts: 92, Reputation: 6
    Junior Member
     
    #2

    Dec 13, 2005, 05:06 PM
    Use the Law of Cosines
    Let a, b, and c be the lengths of the legs of a triangle opposite angles A, B, and C. Then the law of cosines states

    a^2 = b^2+c^2-2bccosA
    b^2 = a^2+c^2-2accosB
    c^2 = a^2+b^2-2abcosC.

    Solving for the cosines yields the equivalent formulas
    cosA = (-a^2+b^2+c^2)/(2bc)
    cosB = (a^2-b^2+c^2)/(2ac)
    cosC = (a^2+b^2-c^2)/(2ab).
    Greek2Me's Avatar
    Greek2Me Posts: 9, Reputation: 1
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    #3

    Sep 25, 2009, 04:38 PM

    Check out these articles for a simple tool and tutorial that will make trig simple enough for ANYBODY to do!

    How to Pass That Trigonometry Exam (Without Losing Your MIND!) Part II - Unknown Angles | eHow.com

    How to Pass That Trigonometry Exam (Without Losing Your MIND!) Part I - Unknown Sides | eHow.com
    Greek2Me's Avatar
    Greek2Me Posts: 9, Reputation: 1
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    #4

    Oct 16, 2009, 09:55 AM
    Sorry, duplicate

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