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    Loloo's Avatar
    Loloo Posts: 3, Reputation: 1
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    #1

    Oct 15, 2010, 11:49 AM
    How many ordered pairs of integers (x,y) are there such that 0 < |xy| ≤ 5?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Oct 15, 2010, 11:58 AM

    Could you repost the last symbol or say what it is?
    Loloo's Avatar
    Loloo Posts: 3, Reputation: 1
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    #3

    Oct 15, 2010, 12:05 PM
    It means less or equal to 5
    Loloo's Avatar
    Loloo Posts: 3, Reputation: 1
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    #4

    Oct 15, 2010, 12:08 PM
    Comment on Unknown008's post
    It means less or equal to 5
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #5

    Oct 15, 2010, 12:56 PM

    I'm not sure how to go about it with strict calculations, but with guesswork, we can get them all.

    -1 and -5 and vice versa
    1 and -5 and vice versa
    -1 and 5 and vice versa
    1 and 5 and vice versa

    That's it :)

    EDIT: Now, you need to look for those pairs which form less than 5.

    Which are (1|1), (1|2), (2|2), (1|3), (1|4) pairs with plus and minus signs.

    This makes some more pairs to add.
    kpg0001's Avatar
    kpg0001 Posts: 88, Reputation: 12
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    #6

    Oct 15, 2010, 01:04 PM

    What about (1,4),(1,3),(1,2),(1,1),(2,2) with all the -/+ and vise versas? I mean the only rules are that when multiplied together the absolute value has to be greater than zero but less than or equal to 5 right? And that is just whole numbers. In reality there is an infinite number of pairs that could fit. Am I missing something?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #7

    Oct 15, 2010, 11:04 PM

    Yes, I'm the one who missed something. After a good night of sleep, I realised my mistake but you had already posted before I was able to come online :o
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