[lockhart11]

I need the answer

[ebaines]

The trick here is to convert the cosecant function into its equivalent sin function, using:

csc(x) = 1/sin(x).

Can you take it from here?

[Unknown008]

If that is to be proved, then you use what ebaines suggested.

If you need to solve for x... well, you need to think about the proof ;)

[ebaines]

Just one little "gotcha" to add - think about the range of csc(x), and avoid a situation of trying to determine a value for

[galactus]

Look at what sin(x)csc(x) is.

Since csc(x)=1/sin(x), then we have sin(x)/sin(x).

Of course, it equals 1 no matter the x value.

[ebaines]

Of course, it equals 1 no matter the x value.

Actually, sin(x)csc(x) is undefined at x = 0.

[galactus]

Actually, sin(x)csc(x) is undefined at x = 0.

Yes, of course. I reckon I should have been more definitive.

[InfoJunkie4Life]

For all values of x such that 0 is less than x is less than pi and pi is less than x is less than two times pi.



I can't think of a better way to write it...

[ebaines]

I can't think of a better way to write it...

How about:
For , where = any integer.

[InfoJunkie4Life]

Ah... I was wondering how you would say "x cannot be a factor of pi" but I wasn't sure. That works great.