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ramsdale · Apr 24, 2010, 10:56 AM

transpose D=15log(pont/pin) change subject to pin

ebaines · Apr 27, 2010, 11:18 AM

Assuming that you are using natural logs here, the only issue here is to remember that if a = ln(b), then e^a =b:

$ D = 15 ln(\frac {pont} {pin}) \\ \frac D {15} = ln (\frac {pont} {pin} ) \\ e^{(D/15)} = \frac {pont} {pin} \\ pin = \frac {pont} {e^{(D/15)} }= pont \ \times \ e^ {(-D/15)} $

Unknown008 · Apr 28, 2010, 08:36 AM

A side note ebaines:

I think that it was P_in and P_out :)

$P_{in}$ $P_{out}$

ebaines · Apr 28, 2010, 12:56 PM

Originally Posted by Unknown008

A side note ebaines:

I think that it was P_in and P_out :)

$P_{in}$ $P_{out}$

Perhaps it was - although in that case the OP misspelled P_out, twice...