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    princess94's Avatar
    princess94 Posts: 3, Reputation: 1
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    #1

    Mar 7, 2010, 06:15 PM
    how do you factor by grouping 6v^3-16v^2+21v-56?
    How do you factor by grouping this.
    1flwrgrl's Avatar
    1flwrgrl Posts: 15, Reputation: 4
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    #2

    Mar 7, 2010, 09:10 PM

    What in the world is ^ that sign?
    KISS's Avatar
    KISS Posts: 12,510, Reputation: 839
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    #3

    Mar 7, 2010, 09:35 PM

    Princess means this:

    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Mar 8, 2010, 06:49 AM

    Well, I had some trouble with that. It's a trial and error method.

    If

    Then, if (v-a) is a factor of f(v), then f(a) = 0.

    So, you have to find the value of a for which f(a) = 0.

    I tried f(1), giving f(1) = 6(1)^3 - 16(1)^2 + 21(1) - 56 = -45.

    So, (v - 1) is not a factor.

    I won't show everything I tried, it would be a mess, but I got (v - 8/3)

    Check:



    So, (3v - 8) is a factor of f(v).

    Now, you can divide (6v^3 - 16v^2 + 21v - 56) by (3v - 8)

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