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fatman55 · Feb 28, 2010, 08:56 PM

Solid aluminum bromide and chloride gas react to produce bromine and solid aluminum chloride.

chemical equation?

starfirefly · Feb 28, 2010, 09:46 PM

AlBr + Cl = Br + AlCl

single replacement is what is used... sorry I don't have the proper numbers for the atoms but they should be on you perodic table with the +-

Unknown008 · Mar 1, 2010, 08:16 AM

I have to disagree starfirefly. These are not the proper formulae.

Aluminium bromide - consist of aluminium and bromide ions, aluminium having a valency of 3 and bromide a valency of 1. This makes aluminium bromide have the formula $AlBr_3$

Chlorine gas has the formula: $Cl_2$

Aluminium chloride is written as $AlCl_3$

And bromine liquid is written as $Br_2$

The equation becomes:

$AlBr_3 + Cl_2 \rightarrow AlCl_3 + Br_2$

Now to balance, you need one more chlorine ion on the left, and one more bromine ion on the right. You need to put 3/2 in front of Cl2 and 3/2 in front of Br2. This way, you have 2* 3/2 = 3 chlorine atoms and 2 * 3/2 = 3 bromine atoms.

$AlBr_3 + \frac32 Cl_2 \rightarrow AlCl_3 + \frac32 Br_2$

The equation is now balanced. To remove the fractions, just multiply everything by 2.

$2AlBr_3 + 3 Cl_2 \rightarrow 2AlCl_3 + 3 Br_2$

You can count the atoms on the left and right. They are the same.