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    raynisha's Avatar
    raynisha Posts: 4, Reputation: 1
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    #1

    Feb 24, 2010, 05:47 PM
    there are 18 girl and 12 boys on student council. If two student council member are s
    there are 18 girl and 12 boys on student council. If two student council member are selected at random, what is the probability that the first member is a boy and the second member is a boy?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Feb 25, 2010, 02:34 AM

    The probability for the first member is a boy is the number of boys divided by the total number of students.

    Now that you got that, there is one boy less and the total number of students are reduced by one.

    To get the probability that the second member is a boy, divide the number of boys left by the number of students left.

    Post your answers :)
    starfirefly's Avatar
    starfirefly Posts: 397, Reputation: 33
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    #3

    Feb 25, 2010, 02:29 PM

    first put your ration into lowest terms example 18:12= 3:2 go from there
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Feb 26, 2010, 10:29 AM
    Quote Originally Posted by starfirefly View Post
    first put your ration into lowest terms example 18:12= 3:2 go from there
    No, I'm sorry to disagree, but it's not like that.

    The probability to have the first boy chosen is 12/30.

    The probability of having the second boy chosen is 11/29 (since there is one boy less and one student from the total less)

    Now, for both situations to occur together, you multiply the two probabilities, giving 66/435
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #5

    Feb 27, 2010, 06:42 AM

    Another way to look at it is with combos.

    .

    Which agrees with Unknown, but reduced to simplest terms.
    Cricket2009's Avatar
    Cricket2009 Posts: 2, Reputation: 1
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    #6

    Feb 28, 2010, 10:04 PM
    Quote Originally Posted by Unknown008 View Post
    No, I'm sorry to disagree, but it's not like that.

    The probability to have the first boy chosen is 12/30.

    The probability of having the second boy chosen is 11/29 (since there is one boy less and one student from the total less)

    Now, for both situations to occur together, you multiply the two probabilities, giving 66/435

    Yup, this makes sense
    AK lawyer's Avatar
    AK lawyer Posts: 12,592, Reputation: 977
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    #7

    Jan 27, 2011, 12:24 AM
    Never mind.
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