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texasbluemoon · Feb 21, 2010, 11:12 AM

How does one measure the volume of a hexagonal cell? For example, a container with one closed end and hexagonal sides measuring four feet wide,(space between any two plane sides of said hexagon) and five feet in depth. How much liquid could a container of this size hold?

Unknown008 · Feb 21, 2010, 11:32 AM

Do you mean a prism with a hexagonal cross section?

aavery2009 · Jun 3, 2010, 11:20 AM

Yes

galactus · Jun 3, 2010, 11:55 AM

Knowing the side length, the area of any regular polygon can be found by using

$\text{Area}=\frac{L^{2}n}{4tan(\frac{\pi}{n})}$

n=number of sides
L=side length

If you use a calculator make sure it is in radian mode.

For degree mode use $\frac{L^{2}n}{4tan(\frac{180}{n})}$

To find volume, multiply your result by the height of the container. In this case, 5.

This will be in cubic feet. To convert it to, say, gallons, multiply by 7.48