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    starfirefly's Avatar
    starfirefly Posts: 397, Reputation: 33
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    #1

    Oct 29, 2009, 07:50 PM
    finding slope?
    I'm really stuck on this question... my math examples skip steps and I don't understand it this is what it says.. all I need to know is what steps are missing any help would be appreciated.



    2x-5y=4
    -5y=-2x+4 after this I'm so lost
    y=2/5x-4/5
    slope is 2/5
    KISS's Avatar
    KISS Posts: 12,510, Reputation: 839
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    #2

    Oct 29, 2009, 08:44 PM

    Seems simple enough:

    2x-5y=4

    Actually, you just want the form y = mx+b, then m is the slope and b is the y intercept (x=0)

    You want a positive y, so you nned to re-arrange the eqn as:

    2x=5y+4 ; all I did here was make y positive

    re-arranging as close to y = mx +b

    2x-4 = 5y

    re-arrange again

    a) 5y=2x-4

    almost. Now get y by itself by dividing by 5

    y = 2/5(x) - 4/5

    slope is 2/5

    or, from where you got lost

    -5y=-2x+4

    multiply both sides by -1;

    and your at my eqn labeled a

    5y = 2x -4

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