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    Mady07Senior's Avatar
    Mady07Senior Posts: 1, Reputation: 1
    New Member
     
    #1

    Oct 25, 2006, 04:30 PM
    multiplying radical exponents
    How would you solve this problem:

    3^ radical 4 times 3^ radical 16

    (If that even makes sense)

    I REALLY could use some help on algebra 2! Thankx
    electr0's Avatar
    electr0 Posts: 18, Reputation: 0
    New Member
     
    #2

    Oct 25, 2006, 05:26 PM
    You would simplify it into: from the square root of 4 times the squre root of 16, first you would do square root of 4 which is 2 and then the square root of 16 which is 4.
    So that leaves you with 2 times 4 which is 8. :)

    (I think that was your question because I didn't understand what the "3^" meant)

    Hope that helps. :D
    Ace High's Avatar
    Ace High Posts: 191, Reputation: 22
    Junior Member
     
    #3

    Oct 25, 2006, 05:52 PM
    3^[radical symbol]4=9
    3^[radical symbol]16=81
    9x81=729


    -chainer (I was just walking by, saw comp, and decided to put my answer)
    s_cianci's Avatar
    s_cianci Posts: 5,472, Reputation: 760
    Uber Member
     
    #4

    Oct 28, 2006, 01:20 PM
    rewrite it as:

    3^2 * 3^4

    add the exponents:

    3^6

    simplify:

    729

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