Ask Experts Questions for FREE Help !
Ask
    roberts61's Avatar
    roberts61 Posts: 13, Reputation: 1
    New Member
     
    #1

    Apr 26, 2009, 04:50 AM
    mass of air
    The mass of 1 m" of dry air at standard temperature and pressure is 1.29 kg;
    therefore the mass of dry air in a room 8 x 6 x 4 m, at an atmospheric pressure of
    96 kPa and a temperature of 20°C, is:
    400410
    A 195 kg
    B 201 kg
    C 206 kg
    D 219 kg

    if anyone can answer this rubic cube of a question, please include the calculations
    cheers
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
    Ultra Member
     
    #2

    Apr 26, 2009, 05:01 AM

    The mass of 1 cubic meter (?) of air is 129 kg. The mass of air is proportional to its volume.

    The "combined gas law" (combining Boyle's, Charles, and Gay-Lussac's laws) is:



    at STP,
    P1 = 1 atm = 101.32500 KPa
    P2 = 96 KPa
    V1 is unknown for the volume specified.
    V2 is given, 8 x 6 x 4 m = 192 m^3
    T1 at STP is 273.15 Kelvins (0 °C).
    T2 is 293.15 Kelvins (20 °C)

    Solve the equation for V1 (the volume at STP). Set up a ratio equation wherein 1 cubic meter is to 129 Kg as V2 cubic meters is to the unknown weight. Solve for the unknown weight.

    I've set it up for you. You can do the math.

    This should have been put under Chemistry or possibly Physics.
    roberts61's Avatar
    roberts61 Posts: 13, Reputation: 1
    New Member
     
    #3

    Apr 27, 2009, 02:26 AM
    Quote Originally Posted by Perito View Post
    The mass of 1 cubic meter (?) of air is 129 kg. The mass of air is proportional to its volume.

    The "combined gas law" (combining Boyle's, Charles, and Gay-Lussac's laws) is:



    at STP,
    P1 = 1 atm = 101.32500 KPa
    P2 = 96 KPa
    V1 is unknown for the volume specified.
    V2 is given, 8 x 6 x 4 m = 192 m^3
    T1 at STP is 273.15 Kelvins (0 °C).
    T2 is 293.15 Kelvins (20 °C)

    Solve the equation for V1 (the volume at STP). Set up a ratio equation wherein 1 cubic meter is to 129 Kg as V2 cubic meters is to the unknown weight. Solve for the unknown weight.

    I've set it up for you. You can do the math.

    This should have been put under Chemistry or possibly Physics.
    Perito
    thanks for your help, I've still not figured out the answer yet, but I'm sure I will.
    thanks again
    peter
    SolveWatt's Avatar
    SolveWatt Posts: 1, Reputation: 1
    New Member
     
    #4

    Mar 23, 2016, 11:02 AM
    D.) 219 = 1.29 x 273/293 x 96/101 x 192

Not your question? Ask your question View similar questions

 

Question Tools Search this Question
Search this Question:

Advanced Search

Add your answer here.


Check out some similar questions!

Mole mass of a pea? [ 14 Answers ]

If you have a mole of peas and each pea has a mass of 1.4g, what mass of peas do you have ? Just wondering, did my teacher make a mistake on this question? Because he doesn't state how many peas I'm solving for.. it seems like the important part of the question is missing. Any thoughts?

Mass percentage [ 1 Answers ]

Vinegar (0.9862 g) was titrated withj 0.120 M NaOH. 26.28 cm3 were required. What is the (mass) % CH3COOH in the vinegar? I got an answer of 19.2% but I'm not sure can anyone help

Mass [ 1 Answers ]

A thin circular sheet of aluminum has a radius of 20 cm and a thickness of 0.50 mm. Find the mass of the sheet.

Mass [ 4 Answers ]

What mass of lead(II) nitrate is present in 20.0mL of a solution? See below. Two different lead(II) nitrate solutions are used, each sample is reacted with an excess quantity of a potassium iodide solution, which produces lead(II) iodide.


View more questions Search