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Daniella13 · Jan 15, 2009, 09:14 AM

How do you solve a circle equation without having the radius
Ex. R ^2= (5-h)^2+(5-k)^2 ?

harum · Jan 15, 2009, 09:01 PM

What do you want to get as an answer? What does it mean to solve a circle euqation to you? How many variables do you have in this "circle" equation?

galactus · Jan 16, 2009, 01:05 PM

A circle equation is $(x-h)^{2}+(y-k)^{2}=r^{2}$

Where (h,k) is the coordinates of the center and (x,y) is a point on the circle.

In your case, (x,y)=(5,5), a point on the circle. That's about it. What is it you want to solve?

We have no center coordinates nor radius. The way it is there are a infinite number of circles that could meet that.

juhi2011 · Jan 18, 2009, 10:43 PM

What is required by you in the answer is not clear.

abelle · Dec 26, 2009, 03:03 AM

Originally Posted by harum

What do you want to get as an answer? What does it mean to solve a circle euqation to you? How many variables do you have in this "circle" equation?

How do I find centre of circle? When equation=(x-1)^2+(y-k)^2=10, and circle co-ordinates (2,5)

Unknown008 · Dec 26, 2009, 04:23 AM

abelle, have to taken notice of galactus' post a little above?

There are all the explanations for your problem there.

You have a point on the circle, (2, 5).

Find 'k' the y-coordinate of the circle that you don't have. You already have the x-coordinate of the centre of circle as 1 here.