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    nett's Avatar
    nett Posts: 1, Reputation: 1
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    #1

    Feb 26, 2004, 02:08 AM
    Homework problem
    Here is a homework question for my 11 year nephew
    " A father is 4 times as old as his son. In 6 years time he will be only 3 times as old. How old is each of them.
    LTheobald's Avatar
    LTheobald Posts: 1,051, Reputation: 127
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    #2

    Feb 26, 2004, 08:36 AM
    Homework problem
    I don't know if there is an easy way to find out the answer, but I got it through trial and error.

    If the son is 12, he's dad will be 48.
    In 6 years, he will be 18 and his dad will be 54.

    48 / 4 = 12
    54 / 3 = 18
    MathMaven53's Avatar
    MathMaven53 Posts: 20, Reputation: 2
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    #3

    Mar 26, 2004, 09:57 AM
    Re: Homework problem
    Let S be son's age now. Then in 6 years he will
    be S + 6 years old
    Let F be father's age now. Then in 6 years he will be
    F + 6 years old

    Now the father is 4 times as old as his son

    F = 4S

    In 6 years the father is 3 times as old as his son

    F + 6 = 3(S + 6)

    We solve this system of equations for F and S

    Substitute the first equation into the second

    4S + 6 = 3(S + 6)

    4S + 6 = 3S + 18

    S = 12

    So the son is 12 years old and
    the father is 48 years old

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