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    Sami A's Avatar
    Sami A Posts: 1, Reputation: 1
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    #1

    Mar 2, 2006, 10:12 PM
    trig equations
    solve the following for 0 is less than or equal to x which is less than or equal to 2pie
    sinxcscx-cscx+2sin=0
    dmatos's Avatar
    dmatos Posts: 204, Reputation: 26
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    #2

    Mar 3, 2006, 08:51 PM
    First thing to do - try to simplify this equation. Note that cscx = 1/sinx:

    sinxcscx = 1

    1 - 1/sinx + 2sinx = 0

    Well, this looks like it could become a fairly simple quadratic equation with a bit of manipulation. Multiply both sides of the equation by sinx. Then, let y=sinx, and you should see a nice quadratic equation in y.

    Solve the quadratic equation for y (you'll get 2 answers). Then, you have sinx = y. Solve this (I believe the numbers are straightforward - use the inverse trig functions on the calculator if you don't recognize the values). I'm pretty sure the two possible values for y give me three possible values for x that lie between 0 and 2pi (mmm... pie... )

    Hope that helps!

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