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    UnSolon's Avatar
    UnSolon Posts: 9, Reputation: 1
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    #1

    Jan 26, 2006, 08:20 AM
    Pre-Calculus - first the basics
    Find the points of intersection of the graphs of the equations:
    x^2 + y^2 = 5
    x - y = 1

    Pretty basics, but lets see who's up on calc.
    fredg's Avatar
    fredg Posts: 4,926, Reputation: 674
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    #2

    Jan 26, 2006, 08:49 AM
    Hi,
    x intercepts are -1 and 2
    y intercepts are -2 and 1
    reinsuranc's Avatar
    reinsuranc Posts: 92, Reputation: 6
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    #3

    Jan 26, 2006, 09:24 PM
    A few more details
    x^2 + y^2 = 5
    x = y + 1
    (y+1)^2 + y^2 = 5
    y^2 +2y +1 +y^2 - 5 =0
    2y^2 + 2y -4 = 0
    y^2 +y -2 = 0
    (y + 2)(y - 1) = 0
    y roots are -2 and +1.
    corresponding x values are -1 and 2.

    Solutions are (-1,-2), (2,1)
    UnSolon's Avatar
    UnSolon Posts: 9, Reputation: 1
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    #4

    Jan 26, 2006, 11:02 PM
    Very good... correct on all counts
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