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Solving Functions
Knowing f(x)=x^2+x and g(x)=2x+1 how would you solve f(g(x)) and
(g (circle) f)(4)?? How do you determine the f^(-1) of f(x)=3x-2? Is x+2/3 correct? Thanks |
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My attempt - two out of three
A.
f(u)=u^2+u and g(x)=2x+1 Let u=g(x)=2x+1 f(g(x))=f(u)=(2x+1)^2+(2x+1). B. I don't understand the next part of the problem. You have not defined g(circle)f. C. y=f(x)=3x-2 x=(y+2)/3=f^(-1) |
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Let f(x)=5x^2-4x and g(x)=5x+1
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Let f(x)=5x^2-4x and g(x)=5x+1
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Damian616, please, start your own thread. |
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The circle thing can be read as "of" It is just a different form of notation... it will be the same as g of f of x. |
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