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    phoenirius's Avatar
    phoenirius Posts: 34, Reputation: 1
    Junior Member
    		  
    #1

    Dec 29, 2005, 03:52 PM
    Solving for complex roots
    I have to solve 4x^2 -2x=-1 for its complex roots, this is what I have so far
    4x^2-2x=-1
    4x^2-2x-1=0
    a=4, b=(-2), c=(-1)

    x=-b +- sqrt b^2-4ac / 2a
    =-4 +- sqrt (-2)^2-4(4)(-1) / 2(4)
    =-4 +- sqrt (-4) +16 / 8
    =-4 +-sqrt12/8
    =-4+- sqrt3 * sqrt4/8

    Now I'm stuck, it seems like I did something wrong because I don't know how to finish it off. Can anybody help me.
    Thank you.
    CaptainForest's Avatar
    CaptainForest Posts: 3,645, Reputation: 393
    Ultra Member
    		  
    #2

    Dec 29, 2005, 08:08 PM
    You wrote:
    4x^2-2x=-1
    4x^2-2x-1=0
    a=4, b=(-2), c=(-1)

    You should have wrote:
    4x^2-2x=-1
    4x^2-2x+1=0
    a=4, b=(-2), c=(1)

    It is not -1=0, it is +1=0
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