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    phoenirius's Avatar
    phoenirius Posts: 34, Reputation: 1
    Junior Member
     
    #1

    Dec 23, 2005, 11:44 AM
    Are these Values Correct for These Equations and/or how to do I check?
    Vertex AS Domain Range MIN/MAX
    Y=0.5x^2 (0,0) X=0 all real numbers y<=0 MIN = 0
    Y=0.5x^2-3 (0,-3) X=0 all real numbers y>=-3 MIN = -3
    Y=0.5(x+4)^2 (0.0) X=0 all real numbers y<=0 MIN =0
    Y=0.5(x+4)^2-3 (0,-3) X=0 all real numbers y>=-3 MIN = -3


    Thanks!
    reinsuranc's Avatar
    reinsuranc Posts: 92, Reputation: 6
    Junior Member
     
    #2

    Jan 5, 2006, 12:25 AM
    Start with the quadratic in the form y = a*x^2 + b*x + c. If the quadratic is not in that form, manipulate it until it is.

    If a>0, the parabola is U-shaped; if a<0, the parabola is upside-down u-shaped.

    If a>0, the minimum y value is at the point called the vertex. (If a<0, the maximum y value is at the point called the vertex.) The vertex (h,k) is found by calculating h = -b/(2a), and then substituting that x value to find the corresponding y value for k.

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