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New Member
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Dec 12, 2007, 01:28 PM
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algebra
4x/(x-3) - 2x / (x-2)
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Full Member
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Dec 12, 2007, 01:38 PM
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Do you have a question or are we supposed to guess?
Whatever your question, show your work and we'll help you out.
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Junior Member
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Dec 12, 2007, 04:47 PM
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Use the following method:
a/b + c/d = (ad + bc)/bd
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New Member
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Dec 13, 2007, 03:16 AM
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4x/x-3 - 2x/x-2
4x(x-2) - 2x(x-3)/x-3*x-2
4x^2-8x-2x^2+6x/x-3*x-2
2x^2-2x/x-3*x-2
2(x^2-1)/x^2 - 5x - 6
this must b the answer
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New Member
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Dec 21, 2007, 07:46 AM
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wouldn't the answer be 2x^2 - 14x:confused:
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New Member
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Dec 21, 2007, 08:44 AM
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I wiil try to solve it once again... but I think that must be the answer... I willl try once again
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New Member
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Dec 21, 2007, 08:50 AM
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No... the answer u are telling is not correct... so try it again
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Junior Member
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Dec 21, 2007, 04:53 PM
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4x/(x-3) - 2x / (x-2)
= [4x (x -2 ) -2x (x -3)]/(x-3)(x-2)
= (4x^2 - 8x - 2x^2 + 6x)/(x-3)(x-2)
= (2x^2 -2x)/(x-3)(x-2)
= 2x (x -1)/(x -3) (x -2)
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New Member
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Jan 3, 2008, 01:49 AM
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2^x+4x-1
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New Member
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Jan 3, 2008, 02:02 AM
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Originally Posted by mgots
4x/(x-3) - 2x / (x-2)
4x/x-3-2x/x-3=4x(x-2)-2x(x-3)=4x^2-8x-2x^2+6x=2x^2-2x=1
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