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Slimboyie · Nov 3, 2007, 06:08 PM

Can someone explain to me how to solve this equation:

(4/9)-1/2*

*Exponent

??

terryg752 · Nov 4, 2007, 05:31 PM

Originally Posted by Slimboyie

Can someone explain to me how to solve this equation:

(4/9)-1/2*

*Exponent

???

(4/9)-1/2*

= (9/4)1/2*

= Square root of (9/4)

= (Square root of 9)/(Square root of 4)

nycfunction · Nov 11, 2007, 11:33 AM

Originally Posted by Slimboyie

Can someone explain to me how to solve this equation:

(4/9)-1/2*

*Exponent

???

RULE:

a^(-b) = 1/a^(b)

We can use this rule to solve your negative fractional exponent question.

4/9 raised to the negative fraction -1/2 becomes 1/(4/9)^(1/2)... Notice that the fraction 1/2 became POSITIVE when moved to the right side of the equation. See it?

Our denominator--->this guy--> (4/9)^(1/2) can be written as a square root. We now have the square root of 4/9, which 2/3.

Our new fraction is 1/(2/3).

What is 1 divided by 2/3?

Final answer: 3/2.

bryndle · Oct 20, 2011, 03:17 PM

(x^(1/2)-2x^(-1/2))/(x^(-1/2))

ebaines · Oct 21, 2011, 06:13 AM

bryndle - please do not tag a new question onto an old thread. Instead you should start a new question. But to help out...

Remember that:

$<br /> \frac {x^a} {x^b} = x^{(a-b)}<br />$

For example:

$<br /> \frac {x^{1/2)}} {x^{-(1/2)}} = x^{(1/2 - (-1/2))} = x<br />$
can you take it from here?