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    wateverlala's Avatar
    wateverlala Posts: 2, Reputation: 1
    New Member
     
    #1

    Oct 25, 2007, 05:53 PM
    More algebra 1
    Armando and drew do volunteer work at an animal shelter. Drew worked 3 more hours than armando, and together they worked more than 27 hours. What is the least number of hours each worked?:confused: :confused: :eek:
    sGt HarDKorE's Avatar
    sGt HarDKorE Posts: 656, Reputation: 98
    Senior Member
     
    #2

    Oct 25, 2007, 06:20 PM
    Lets have Drew = x
    and Armando = y

    y=x+3
    x+y>27

    x+(x+3)=27

    2x+3=27
    2x=24
    x=12

    12+y=27
    y=15

    The least amount they worked was

    x>12
    y>15

    because they worked more than 27 hours so it has to be greater than a total of 27

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