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    wateverlala's Avatar
    wateverlala Posts: 2, Reputation: 1
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    #1

    Oct 25, 2007, 05:01 PM
    algebra 1
    find the greatest possible pair of integers that one integer is twice the other and their sum is less than 30.
    Gernald's Avatar
    Gernald Posts: 901, Reputation: 93
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    #2

    Oct 25, 2007, 06:05 PM
    Less then thirty or 30 exactly?
    Start with numbers that can be halved that eliminates most. Then start adding them up and try to get 30 or below thirty.
    like 2 and 4 then 2+4=6 that makes it but its not the greatest it can be.
    try higher numbers like 20 and 10 20+10 makes exactly thirty but its not right because it has to be less then thirty.
    So since 19 won't work try 18 and its half 9. 18+9=27
    wallla an answer.
    I'm sure there's an easier way to do it, but I always like to think it out logically because I can't stand math.
    eawoodall's Avatar
    eawoodall Posts: 230, Reputation: 5
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    #3

    Oct 27, 2007, 12:16 AM
    a +b <30.
    b=2a.
    a +2a <30.
    3a <30.
    a <10.
    what is the biggest integer less than ten?
    nine.
    a=9.
    b = 2a = 2(9) =18.
    b =18.
    9 +18 <30.
    27 <30.
    true.

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