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    YAMI's Avatar
    YAMI Posts: 2, Reputation: 1
    New Member
    		  
    #1

    Oct 14, 2005, 08:54 PM
    Percentages
    A Certain Brass Alloy Contains 60% Copper , 34% Zinc, And 6% Lead. How Many Kg Of This Brass Alloy And Of Zinc Must Be Added To 20 Kg Of Lead To Produce A New Brass Alloy That Is 40% Zinc And 8% Lead.


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    reinsuranc's Avatar
    reinsuranc Posts: 92, Reputation: 6
    Junior Member
    		  
    #2

    Oct 26, 2005, 08:21 PM
    I'll set it up - you solve it
    Currently Lead has 20 kg and is 6% of what total? 20 = 6% of X, X = 20/6% = 333.33 kg.

    Currently Copper is 60% of 333.33 = 200 kg. Currently Zinc is 34% of 333.33 = 113.33 kg.

    Let's add C kg of Copper and Z kg of Zinc. The new total will be (200 + C) + (113.33 + Z) + 20.

    The Zinc will be 40% of the new total, and the Lead will be 8% of the new total:

    Zinc: (113.33 + Z) = 40%[(200 + C) + (113.33 + Z) + 20]
    Lead: 20 = 8%[(200 + C) + (113.33 + Z) + 20]

    The above is two equations in two unknowns, which you should be able to solve for C and Z.
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