[ahhhhh]

I really need help with alg II.:confused:

problems :
f(a) = 2a + 3
f(x) = -x - 7
f(h) = -6h - 2/3
f(y) = -3y - 2
f(d) = 1 - 4d
f(x) = 5/6x + 1/2
f(z) = z + 9.5
f(x) = 2x - 3
f(t) = 1/2t - 2

[ebaines]

What are you trying to do - draw a graph of each of these functions?

[ahhhhh]

What are you trying to do - draw a graph of each of these functions?

Err I don't really know
It's the first time I've been in this class

The directions are 'for each function, find f (-5)

[ebaines]

OK. I'll help you with the first problem, then maybe you can do the rest.

The problem is: f(a) = 2a+3.

A function is sort of like a machine, where you stick a number in for the independent variable (in this case, for "a"), "turn the crank," and out comes a second number for f(a). In this case you stick in a value for "a" and see what comes out. So, when they ask for f(-5), what they want is for you to stick -5 in place of the "a" and see what you get. What you have here is f(-5) = 2 x -5 + 3 = -7. So, f(-5) = -7.

Now, can you do the rest?

[s_cianci]

Plug -5 into each variable and do the arithmetic.