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    dks2114's Avatar
    dks2114 Posts: 32, Reputation: 2
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    #1

    Jul 25, 2007, 07:42 AM
    Optimization
    Hello everyone! I came across this problem in my homework and I've been having a lot trouble with it. If anyone could tell me how to solve it or at least where to start that would be amazing.;)

    thank you very much!

    For a fish swimming at a speed v relative to the water, the energy expenditure per until time is proportional to v^3. It is believed that migrating fish try to minimize the total energy required a fixed distance. If the fish are swimming against a current u (u<v) then the time required to swim a distance L is L / (u-v) and the total energy required to swim the distance is given by:

    E(v)= (av^3) ( L/ v-u)

    where a is a proportionality constant.

    a) Determine the value of v that minimizes E.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Jul 25, 2007, 10:05 AM
    I won't solve this for you, but here's the approach to use:

    First, take the derivative of E(v) with respect to v, and find for what value of v the derivative is equal to 0. This value will give either a minimum or a maximum for E(v). To determine which it is, you calculate the second derivative at that point - if the 2nd derivative is a positive value, then the function is "bath tub shaped," and you have a local minimum. If the 2nd derivative is positive, then the function is an inverted bath tub, and you have a local maximum. (Hint - you'll find that for your problem that the first derivative does indeed give a minimum.) Lastly, you should check the boundary values, to ensure that there isn't something funny going on - in this case, what is E(v) for v = u (the min that v can be) and for v = infinity, and how do they compare to the value of the local min you found above?

    All this assumes you now how to take first and second derivatives - post back if you have questions about that. Good luck.

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