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Finding spring constant
A 1000kg safe is 2.0m above a heavy-duty spring when the rope holding the spring breaks. The safe hits the spring and compresses it 50 cm. What is the spring constant of the spring?
GPE = KE mgh = (1/2) mv^2 gh = (1/2) v^2 (9.8)(2) = (1/2) v^2 39.2 = v^2 6.26 m/s KE = EPE (1/2)(1000) (6.26) = (1/2) k (.5^2) 24040N/m = k Is this correct?? |
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