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    tina12181's Avatar
    tina12181 Posts: 1, Reputation: 1
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    #1

    Oct 16, 2011, 09:02 PM
    equations and inequalities with consecutive numbers
    five decreased by eleven times a number is greater than 71. Evaluate this problem situation for values of the number.
    DrJ's Avatar
    DrJ Posts: 1,328, Reputation: 339
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    #2

    Oct 16, 2011, 09:10 PM
    Gosh, it's been a while since I've done this stuff but it seems this would be what you are looking for:

    5-11x>71

    OH yeah, so to finish it would be like this:

    5-11x>71
    -5... -5

    -11x>71-5

    -11x>66
    ---- ----
    -11... -11

    x>-6

    I didn't check that answer against the original formula but it seems right from here.

    (and sorry for the... 's, I had to do that to make it line up in the right spot)
    kkochan's Avatar
    kkochan Posts: 1, Reputation: 1
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    #3

    Nov 8, 2012, 03:25 PM
    the sum of three consecutive integers is 48. What is the set of the three consecutive integers that fit the situation?
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