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    jillholiver's Avatar
    jillholiver Posts: 5, Reputation: 1
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    #1

    Mar 4, 2007, 06:09 PM
    Physics-solving center of gravity problems
    I am doing extra work in my college physics course to try to get in a groove with parallel forces and center of gravity problems. I am stuck. I have navigated my online membership course, RapidMastery for Physics, and I'm still stuck. Any helpful explanations would be appreciated. The problem is this:
    The uniform bar is 5.00m long and swighs 975N. A weight of 255N is attached to one end while a weight of 375N is attached 1.50m from the other end. A. Find the tension in the cable. B. Where should the cable be tied to lift the bar and its weights so that the bar hangs in a horizontal equilibrium position?
    I am working in circles and need help.
    Thank you.
    Jill
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #2

    Mar 5, 2007, 12:29 AM
    What cable??
    jillholiver's Avatar
    jillholiver Posts: 5, Reputation: 1
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    #3

    Mar 5, 2007, 05:04 AM
    The cable is positioned at the 2.00m mark of the cable, labeled in the diagram (sorry!) as F4. The tension of F4 is the "cable".
    Jill
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #4

    Mar 5, 2007, 05:31 AM
    I don't see a diagram, this is the problem. So I'm just going on your description, I will have a look at this in a bit.

    Edit: another question, is the cable the pivot point?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #5

    Mar 5, 2007, 08:28 AM
    Since this seems to me to be a basic moment calculation, I will give you the three equations you need:

    These apply for a stationary pivoted system:

    Moment about pivot = Perpendicular Force x Distance from pivot

    Clockwise moment = Anticlockwise moment

    Downward force = Upward force


    This should be enough for you to do it yourself, but if you need help please feel free to ask :)
    jillholiver's Avatar
    jillholiver Posts: 5, Reputation: 1
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    #6

    Mar 5, 2007, 02:13 PM
    The cable is not the pivot point. The pp is set at the right end of the 5.0 meter bar.
    Jill
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    #7

    Mar 5, 2007, 02:14 PM
    Thank you, capuchin.
    Jill
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #8

    Mar 5, 2007, 02:21 PM
    How are you doing with it? A picture would be useful :)
    jillholiver's Avatar
    jillholiver Posts: 5, Reputation: 1
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    #9

    Mar 5, 2007, 02:26 PM
    I'm on my way back to class. I'll work on it tomorrow and update you then.
    Thanks so much.
    Jill
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #10

    Mar 5, 2007, 02:31 PM
    Okay :)
    turin's Avatar
    turin Posts: 2, Reputation: 1
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    #11

    Jan 25, 2013, 05:55 AM
    How can I find the center of gravity

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