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    Kan418's Avatar
    Kan418 Posts: 4, Reputation: 1
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    #1

    Jul 17, 2009, 03:32 AM
    evaluate the following limits
    lim x2(squared) - 6x + 8 / 2x2(squared) - 32
    x-4 (the - is an arrow)
    iLLyriC's Avatar
    iLLyriC Posts: 36, Reputation: 1
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    #2

    Jul 17, 2009, 05:52 AM
    the easiest way is always L'ohspitals Rule:
    Take the derivative of the numerator and denominator and substitute x, in this case:

    lim (x^2 - 6x +8)/2x^2 - 32 = lim (2x -6)/4x = 2/16 = 1/2
    x->4
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #3

    Jul 17, 2009, 08:47 AM
    Quote Originally Posted by iLLyriC View Post
    the easiest way is always L'ohspitals Rule:
    Take the derivative of the numerator and denominator and substitute x, in this case:

    lim (x^2 - 6x +8)/2x^2 - 32 = lim (2x -6)/4x = 2/16 = 1/2
    x->4
    Right, except 2/16 = 1/8, not 1/2.
    iLLyriC's Avatar
    iLLyriC Posts: 36, Reputation: 1
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    #4

    Jul 17, 2009, 02:01 PM
    Quote Originally Posted by ebaines View Post
    Right, except 2/16 = 1/8, not 1/2.
    LoL, thanks for correcting
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #5

    Jul 17, 2009, 02:14 PM


    If I may, L'Hopital is not needed in this case. But it works OK.

    We are only dealing with a rational function.

    Notice we can factor:

    Kan418's Avatar
    Kan418 Posts: 4, Reputation: 1
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    #6

    Jul 20, 2009, 03:08 AM
    Thank you Galactus.

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