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Type: Posts; User: thinay

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  1. Answers
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    800

    Ok I got it! Thanks! But how about in the next...

    Ok I got it! Thanks! But how about in the next problem? Wherein there are 2 answers? :(
  2. Question: How to prove this?

    by thinay
    Answers
    4
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    1,245

    Wait.. The question in the first problem is that...

    Wait.. The question in the first problem is that I need to show that in the first 48ft rise of the body, it has lost one-half of its velocity..
  3. Question: How to prove this?

    by thinay
    Answers
    4
    Views
    1,245

    Ok! I knew now how to solve it.. thanks! :)

    Ok! I knew now how to solve it.. thanks! :)
  4. Question: How to prove this?

    by thinay
    Answers
    4
    Views
    1,245

    how to prove this?

    Please help in this problem.. Here's the problem:
    A body rises vertically from earth according to the law S= 64t - 16t^2. In here, I need to show or prove that it has lost one-half its velocity in...
  5. Answers
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    Problems in tangents and normals

    Please help me find the solutions in the problems below. I will really appreciate any help. Here it goes...

    In the first problem, find the equation of the line to the ff. conics at the given...
  6. Sure! No problem with me.. :)

    Sure! No problem with me.. :)
  7. Oh.. I see.. I'll be the one to get the second...

    Oh.. I see.. I'll be the one to get the second derivative.. thanks for the help.. Again and again.. :D
  8. Actually not.. its solution is very long.. and I...

    Actually not.. its solution is very long.. and I get confused because of that.. I will go back to the very start and review my solution.. In the end, I end up with nothing.. Still confused on how to...
  9. wait... wait... last one.. I hope you can help me...

    wait... wait... last one.. I hope you can help me in this one.. :D

    in here, not just finding the dy/dx.. but also the d^2y/dx^2..

    here it goes..
    y= sqrt of ((1-cos4x)/(1+cos4x))
    the answer...
  10. Oh.. I see.. tan^2(x+y) is same as (tan(x+y))^2.....

    Oh.. I see.. tan^2(x+y) is same as (tan(x+y))^2.. So, when you break it down that will become (tan(x+y))(tan(x+y)). Since y=tan(x+y)... that will be (y)(y)=y^2..

    I get it.. :D
  11. great! :D hmmm.. I just want to know how...

    great! :D
    hmmm.. I just want to know how
    -1/tan^2(x+y) - 1 become -1/y^2 - 1... :)
  12. haha.. okey! Thanks for the help! Forget about...

    haha.. okey! Thanks for the help!
    Forget about that 'sir' thing.. :D

    I know there's a person here who knows that -(1+y^-2). :)
  13. haha.. okey! Thanks for the help! :D I know...

    haha.. okey! Thanks for the help! :D

    I know there's a person here who knows that -(1+y^-2). :)
  14. Ok! I got it.. I need to expand that to get the...

    Ok! I got it.. I need to expand that to get the correct answer..

    After few minutes, your mouse will start to work again. Be positive. :D

    OK sir.. next number 4.. :)
  15. Oh no.. I mean I got the correct answer in number...

    Oh no.. I mean I got the correct answer in number 3 and not in number 2. :)
  16. I already got the correct answer in number 2! :D

    I already got the correct answer in number 2! :D
  17. Ah.. ok! Now I know what's wrong with my answer...

    Ah.. ok! Now I know what's wrong with my answer in number 1.. My derivative of xsinx is xcosx.. it should be xcosx + sinx..

    I got it! Let's proceed to the next number.. :)
  18. miscellaneous problems in derivatives of trigonometric functions

    please help me solve the problems below. As always, I end up with incorrect answers in some items of my reviewer. Here it is: find dy/dx

    1.) y= xsinx + (1-1/2 x^2)cosx
    Ans: 1/2 x^2 sinx
    my ans:...
  19. Answers
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    707

    Oh.. I see.. my answer is correct which is...

    Oh.. I see.. my answer is correct which is 1-cos2x/2.. I just need to simplify it to get sin^2x..

    In #2, the answer that I got is sec^2 1/2 x.. Its wrong.
  20. Answers
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    707

    derivatives of trigonometric functions

    please help me with this... :) Thanks in advance! When I tried to answer this last two numbers, the answer in the book with mine. And I think my answers are wrong. Here it is:

    1.) y = 1/2 x - 1/4...
  21. Ah.. I see.. the answer in the book is already...

    Ah.. I see.. the answer in the book is already simplified. Tnx! :)
  22. ... but according to the book where we take our...

    ... but according to the book where we take our test the answer in number 4 is this:
    -1/(1+x)(sqrt of 1-x^2)
  23. when I tried solving the 4 items, Ive got the...

    when I tried solving the 4 items, Ive got the correct answer in #s 1 and 2. But in #s 3 and 4, I end up with wrong answers. :( I think my solutions are wrong.

    Here's my answer that I got:
    3.) ...
  24. Derivatives (differentitation of algebraic function)

    hello. Can anyone please help me in these problems.. :) Our prof gave us a long test a day ago.. but sad to say I failed to answer the 4 items in that test. Our prof gave the answers after the test...
  25. Answers
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    949

    Okey! I'm totally done! :D Thank you very much...

    Okey! I'm totally done! :D
    Thank you very much for your help!

    I need to sleep now. Its already 11pm here in our country.

    Hope you can help me again next time! Thanks! More powers! ;)
  26. Answers
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    949

    Hey! I've tried to substitute the value of x to...

    Hey! I've tried to substitute the value of x to g(x)= x/(x-5)..

    if..
    g(6) = 6
    g(7) = 3.5
    g(8) = 2.67
    g(9) = 2.25
    g(10) = 2

    am I correct? :D
  27. Answers
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    949

    Nope! I have read his/her post and I'm just...

    Nope! I have read his/her post and I'm just confused what really the answer is. Because the other one says that the answer is - and the other says that its +.
    That's it! :)
  28. Answers
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    949

    My answer is wr0ng! :DD It should be - infinity..

    My answer is wr0ng! :DD
    It should be - infinity..
  29. Answers
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    949

    Ok! Ok! I'll do that. :) Hey! :D What do you...

    Ok! Ok! I'll do that. :)

    Hey! :D What do you think in this problem? Is it positive or negative infinity?
    lim (x/x+2) + (1/x^2-4)
    x->-2^+

    when I tried to answer it. I end with + infinity.
  30. Answers
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    949

    Ok! Ok! I'll do that. :) Hey! :D What do you...

    Ok! Ok! I'll do that. :)

    Hey! :D What do you think in this problem? Is it positive or negative infinity?
    lim (x/x+2) + (1/x^2-4)
    x->-2^+

    when I tried to answer it. I end with + infinity.
  31. Answers
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    Oh! I see. Thanks a lot! :D

    Oh! I see. Thanks a lot! :D
  32. Answers
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    949

    Thank you for your help! Clap! Clap! Clap! :D ...

    Thank you for your help! Clap! Clap! Clap! :D

    wait. To get the values close to the asymptote.. Am I just going to substitute the value of x..

    example: g(x) = (5.01)/(5.01-5)
    is this correct?...
  33. Answers
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    Is x=5?? :D

    Is x=5?? :D
  34. Answers
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    949

    Wait. I want to know first if my answer 5/0 =...

    Wait. I want to know first if my answer 5/0 = positive infinity correct? :)
  35. Answers
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    Topic: infinite limits

    Can anyone help me with this problem. :)

    The given is: g(x) = x/(x-5) and I need to find the vertical asymptote of the graph of g and the sketch of the graph of g for values close to the...
  36. Answers
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    596

    Oh.. Stupid me. :D now I know my mistake. When I...

    Oh.. Stupid me. :D now I know my mistake. When I add square root of 7.. The answer that I got was square root of 14.

    I forgot that there is invisible 1 before square root of 7. What I did was I...
  37. Answers
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    I end up with an answer: 1/square root of 14 ...

    I end up with an answer:
    1/square root of 14

    Is my answer correct? Because the hand out that was given to us tells that the answer is (square root of 7)/14.

    How did they get that answer? There...
  38. Answers
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    Topic is about Limits

    Can anyone help me in my problem again? Here's my problem in limits:

    Lim ((Square root of 7 + a) - square root of 7) over a
    a->0

    Hope you can help me. Thanks in advance. :)
  39. Answers
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    Thanks for your help galactus! :)

    Thanks for your help galactus! :)
  40. Answers
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    1,062

    ellipse and hyperbola

    The equation of a hyperbola is like this:
    x^2/a^2 - y^2/b^2 = 1

    my problem is this.. I don't know what am I going to do with this equation > 4x^2 - y^2 = 4y
    to become same as the equation...
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