Search:
Type: Posts; User: thinay
Search:
Search took 0.00 seconds.
-
Ok I got it! Thanks! But how about in the next problem? Wherein there are 2 answers? :(
-
Wait.. The question in the first problem is that I need to show that in the first 48ft rise of the body, it has lost one-half of its velocity..
-
Ok! I knew now how to solve it.. thanks! :)
-
Please help in this problem.. Here's the problem:
A body rises vertically from earth according to the law S= 64t - 16t^2. In here, I need to show or prove that it has lost one-half its velocity in...
-
Please help me find the solutions in the problems below. I will really appreciate any help. Here it goes...
In the first problem, find the equation of the line to the ff. conics at the given...
-
Sure! No problem with me.. :)
-
Oh.. I see.. I'll be the one to get the second derivative.. thanks for the help.. Again and again.. :D
-
Actually not.. its solution is very long.. and I get confused because of that.. I will go back to the very start and review my solution.. In the end, I end up with nothing.. Still confused on how to...
-
wait... wait... last one.. I hope you can help me in this one.. :D
in here, not just finding the dy/dx.. but also the d^2y/dx^2..
here it goes..
y= sqrt of ((1-cos4x)/(1+cos4x))
the answer...
-
Oh.. I see.. tan^2(x+y) is same as (tan(x+y))^2.. So, when you break it down that will become (tan(x+y))(tan(x+y)). Since y=tan(x+y)... that will be (y)(y)=y^2..
I get it.. :D
-
great! :D
hmmm.. I just want to know how
-1/tan^2(x+y) - 1 become -1/y^2 - 1... :)
-
haha.. okey! Thanks for the help!
Forget about that 'sir' thing.. :D
I know there's a person here who knows that -(1+y^-2). :)
-
haha.. okey! Thanks for the help! :D
I know there's a person here who knows that -(1+y^-2). :)
-
Ok! I got it.. I need to expand that to get the correct answer..
After few minutes, your mouse will start to work again. Be positive. :D
OK sir.. next number 4.. :)
-
Oh no.. I mean I got the correct answer in number 3 and not in number 2. :)
-
I already got the correct answer in number 2! :D
-
Ah.. ok! Now I know what's wrong with my answer in number 1.. My derivative of xsinx is xcosx.. it should be xcosx + sinx..
I got it! Let's proceed to the next number.. :)
-
please help me solve the problems below. As always, I end up with incorrect answers in some items of my reviewer. Here it is: find dy/dx
1.) y= xsinx + (1-1/2 x^2)cosx
Ans: 1/2 x^2 sinx
my ans:...
-
Oh.. I see.. my answer is correct which is 1-cos2x/2.. I just need to simplify it to get sin^2x..
In #2, the answer that I got is sec^2 1/2 x.. Its wrong.
-
please help me with this... :) Thanks in advance! When I tried to answer this last two numbers, the answer in the book with mine. And I think my answers are wrong. Here it is:
1.) y = 1/2 x - 1/4...
-
Ah.. I see.. the answer in the book is already simplified. Tnx! :)
-
... but according to the book where we take our test the answer in number 4 is this:
-1/(1+x)(sqrt of 1-x^2)
-
when I tried solving the 4 items, Ive got the correct answer in #s 1 and 2. But in #s 3 and 4, I end up with wrong answers. :( I think my solutions are wrong.
Here's my answer that I got:
3.) ...
-
hello. Can anyone please help me in these problems.. :) Our prof gave us a long test a day ago.. but sad to say I failed to answer the 4 items in that test. Our prof gave the answers after the test...
-
Okey! I'm totally done! :D
Thank you very much for your help!
I need to sleep now. Its already 11pm here in our country.
Hope you can help me again next time! Thanks! More powers! ;)
-
Hey! I've tried to substitute the value of x to g(x)= x/(x-5)..
if..
g(6) = 6
g(7) = 3.5
g(8) = 2.67
g(9) = 2.25
g(10) = 2
am I correct? :D
-
Nope! I have read his/her post and I'm just confused what really the answer is. Because the other one says that the answer is - and the other says that its +.
That's it! :)
-
My answer is wr0ng! :DD
It should be - infinity..
-
Ok! Ok! I'll do that. :)
Hey! :D What do you think in this problem? Is it positive or negative infinity?
lim (x/x+2) + (1/x^2-4)
x->-2^+
when I tried to answer it. I end with + infinity.
-
Ok! Ok! I'll do that. :)
Hey! :D What do you think in this problem? Is it positive or negative infinity?
lim (x/x+2) + (1/x^2-4)
x->-2^+
when I tried to answer it. I end with + infinity.
-
Oh! I see. Thanks a lot! :D
-
Thank you for your help! Clap! Clap! Clap! :D
wait. To get the values close to the asymptote.. Am I just going to substitute the value of x..
example: g(x) = (5.01)/(5.01-5)
is this correct?...
-
-
Wait. I want to know first if my answer 5/0 = positive infinity correct? :)
-
Can anyone help me with this problem. :)
The given is: g(x) = x/(x-5) and I need to find the vertical asymptote of the graph of g and the sketch of the graph of g for values close to the...
-
Oh.. Stupid me. :D now I know my mistake. When I add square root of 7.. The answer that I got was square root of 14.
I forgot that there is invisible 1 before square root of 7. What I did was I...
-
I end up with an answer:
1/square root of 14
Is my answer correct? Because the hand out that was given to us tells that the answer is (square root of 7)/14.
How did they get that answer? There...
-
Can anyone help me in my problem again? Here's my problem in limits:
Lim ((Square root of 7 + a) - square root of 7) over a
a->0
Hope you can help me. Thanks in advance. :)
-
Thanks for your help galactus! :)
-
The equation of a hyperbola is like this:
x^2/a^2 - y^2/b^2 = 1
my problem is this.. I don't know what am I going to do with this equation > 4x^2 - y^2 = 4y
to become same as the equation...
|