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Type: Posts; User: MathMaven53
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a b= 0
If a not equal to 0 we can divide both sides by a
a b divided by a equals b
0 divided by a equals 0
Then b = 0
Similarly assume b not equal to 0
Then divide a b=0 by b
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Solve these equations where variables are first letters of their names.
H + F = 120
H + P = 230
P = 6F
Hint: Substitute for P in second equation. Then you have two equations in variables...
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I thought you were summing (-1)^(n-1) (6n)/e^(2n) from n =1 to infinity
The problem you were solving is summing (-1)^(n-1) (6^n)/e^(2n)
My problem involves summing n r^n from n=1 to infinity for...
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1 = 1/2 + 1/2
= 1/2 + (1/2 - 1/3) + 1/3
= 1/2 + 1/3 + 1/6
= 1/2 + 1/3 + 1/7 + (1/6 -1/7)
= 1/2 + 1/3 +1/7 + 1/42
= 1/2 + 1/4 + (1/3-1/4) + 1/7 + 1/42
= 1/2 + 1/4 + 1/7...
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Some times partial fractions can be easily done.
Lets get the function x^2 in terms of x+2
x^2 = [x+2-2]^2
= (x+2)^2 -4(x+2)+ 4
Then x^2 /(x+2)^3 = 1/(x+2) -4(x+2)^2 +4/(x+2)^3...
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Let's express the equation in terms of Sin(x)
We have 2 Cos^2 (x) + Sin(x) =1
We use Cos^2 (x) = 1 - Sin^2(x)
After substituting and simplifying we get the equation
2 Sin^2(x) -...
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1- cot^2 t = 1 - cos^2 t/sin^2 t
= (sin^2 t - cos^2 t)/sin^2 t
= - cos 2t/sin^2 t
Note that cos^2 t - sin^2 t = cos 2t
2sin^2 t = 1 - cos 2t
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1/(1x3) + 1/(2x4) +... + 1/n(n+2) = n(3n+5)/4(n+1)(n+2)
True for n=1
1/(1*3) = 1(8)/[4(2)(3)]
since both sides reduce to 1/3
Assume that
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There are five primes between 1 and 11 inclusive:
2,3,5,7,11
The probability of picking any integer between 1 and 11
inclusive is 1/11 so the probability of picking a prime
between 1 and 11...
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Let S be son's age now. Then in 6 years he will
be S + 6 years old
Let F be father's age now. Then in 6 years he will be
F + 6 years old
Now the father is 4 times as old as his son
F =...
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It's been years since I have studied Physics but I'll
work with the equations and you can substitute values into them.
Let s be distance brick falls,m the mass of the brick, g be...
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Let x be the value two years ago
Then in one year it is worth (3/4)x
In two years it is worth (3/4)[(3/4)x]
This equals (3/4)^2 * x and we know that it also
equals $90
So solve for x...
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:)
(x^m+2)(x^-2)(x^m-5)
= (x^m + 2)x^(m-7)
Used law of exponents for x powers
= x^m x^(m-7) + 2x^(m-7)
Used distributive law
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6x^4=(3x^2)( )
The missing factor must contain 2 since 6=2 * 3
it also contains x^2 since x^4 = x^2 x^2
So 6x^4 = (3x^2)(2x^2)
-35x^2y = (-5xy)( )
The missing factor contains 7 and x
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Where on the internet can I find a free, non-shareware
Math symbol text editor? By non-shareware, I mean that
It will not stop working after 30 days and require payment to get codes to unlock the...
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75 billion dollars times thickness of a dollar bill in inches
Times 1/12 feet per inch divided by 5280 feet per mile
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We are given M+N=3 and M^2 + N^2 =6
Factor M^3 + N^3
M^3 + N^3 = (M+N)(M^2 -MN + N^2)
= (M+N)(M^2 + N^2 - MN)
We have all quantities on the right side except MN
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:) If 2x+1 is a factor of 2x^2 + 7x + k, then
X = -1/2 is a root of 2x^2 + 7x + k = 0
Then by substitution of x=-1/2
2/4 -7/2 + k = 0
Solve for k and you get k=3
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|x^3 - 8| = |(x-2)(x^2 + 2x + 4)|
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I can't draw graphs but I can tell you how to graph these relations.
In question b) solve for x and the graph is a straight vertical line.
In question d) solve for why and the graph is a...
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