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a b= 0
If a not equal to 0 we can divide both sides by a
a b divided by a equals b
0 divided by a equals 0
Then b = 0
Similarly assume b not equal to 0
Then divide a b=0 by b

Solve these equations where variables are first letters of their names.
H + F = 120
H + P = 230
P = 6F
Hint: Substitute for P in second equation. Then you have two equations in variables...

I thought you were summing (1)^(n1) (6n)/e^(2n) from n =1 to infinity
The problem you were solving is summing (1)^(n1) (6^n)/e^(2n)
My problem involves summing n r^n from n=1 to infinity for...

1 = 1/2 + 1/2
= 1/2 + (1/2  1/3) + 1/3
= 1/2 + 1/3 + 1/6
= 1/2 + 1/3 + 1/7 + (1/6 1/7)
= 1/2 + 1/3 +1/7 + 1/42
= 1/2 + 1/4 + (1/31/4) + 1/7 + 1/42
= 1/2 + 1/4 + 1/7...

Some times partial fractions can be easily done.
Lets get the function x^2 in terms of x+2
x^2 = [x+22]^2
= (x+2)^2 4(x+2)+ 4
Then x^2 /(x+2)^3 = 1/(x+2) 4(x+2)^2 +4/(x+2)^3...

Let's express the equation in terms of Sin(x)
We have 2 Cos^2 (x) + Sin(x) =1
We use Cos^2 (x) = 1  Sin^2(x)
After substituting and simplifying we get the equation
2 Sin^2(x) ...

1 cot^2 t = 1  cos^2 t/sin^2 t
= (sin^2 t  cos^2 t)/sin^2 t
=  cos 2t/sin^2 t
Note that cos^2 t  sin^2 t = cos 2t
2sin^2 t = 1  cos 2t

1/(1x3) + 1/(2x4) +... + 1/n(n+2) = n(3n+5)/4(n+1)(n+2)
True for n=1
1/(1*3) = 1(8)/[4(2)(3)]
since both sides reduce to 1/3
Assume that

There are five primes between 1 and 11 inclusive:
2,3,5,7,11
The probability of picking any integer between 1 and 11
inclusive is 1/11 so the probability of picking a prime
between 1 and 11...

Let S be son's age now. Then in 6 years he will
be S + 6 years old
Let F be father's age now. Then in 6 years he will be
F + 6 years old
Now the father is 4 times as old as his son
F =...

It's been years since I have studied Physics but I'll
work with the equations and you can substitute values into them.
Let s be distance brick falls,m the mass of the brick, g be...

Let x be the value two years ago
Then in one year it is worth (3/4)x
In two years it is worth (3/4)[(3/4)x]
This equals (3/4)^2 * x and we know that it also
equals $90
So solve for x...

:)
(x^m+2)(x^2)(x^m5)
= (x^m + 2)x^(m7)
Used law of exponents for x powers
= x^m x^(m7) + 2x^(m7)
Used distributive law

6x^4=(3x^2)( )
The missing factor must contain 2 since 6=2 * 3
it also contains x^2 since x^4 = x^2 x^2
So 6x^4 = (3x^2)(2x^2)
35x^2y = (5xy)( )
The missing factor contains 7 and x

Where on the internet can I find a free, nonshareware
Math symbol text editor? By nonshareware, I mean that
It will not stop working after 30 days and require payment to get codes to unlock the...

75 billion dollars times thickness of a dollar bill in inches
Times 1/12 feet per inch divided by 5280 feet per mile

We are given M+N=3 and M^2 + N^2 =6
Factor M^3 + N^3
M^3 + N^3 = (M+N)(M^2 MN + N^2)
= (M+N)(M^2 + N^2  MN)
We have all quantities on the right side except MN

:) If 2x+1 is a factor of 2x^2 + 7x + k, then
X = 1/2 is a root of 2x^2 + 7x + k = 0
Then by substitution of x=1/2
2/4 7/2 + k = 0
Solve for k and you get k=3

x^3  8 = (x2)(x^2 + 2x + 4)

I can't draw graphs but I can tell you how to graph these relations.
In question b) solve for x and the graph is a straight vertical line.
In question d) solve for why and the graph is a...
