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Type: Posts; User: CommDweeb
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Whew, so formal. :o
To start with I think we are talking about something like a Beach Ball in an indoor swimming pool. If this is wrong, please advise. This problem is more of a materials problem...
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Parabolas perfectly focus light sources that are infinately far away. The closer the light source, the more the distortion. This is not a problem when you are star gazing. A paraboloid is ideal for...
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I think this is what you were asking for.
One of the laws of motion says that "For every action there is an equal and opposite reaction." A force is often referred to as an action. A reaction is...
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Not enough info.
1) Can you look at your D-Link router and at least post a model number?
2) Did your ISP install the Router?
3) Can you directly access the Router's configuration (do you...
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If you go by sheer volume and number of files transferred as well as the number of users I would have to say INN. INN has been in use since the early 1990's at least. It has probably delivered more...
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Well, to start with there really isn't a chemical reaction similar to combustion going.
The ice is simply melting. This absorbs around 100 BTU's per pound of ice melted. What salt does is lower...
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This is a context problem. The meaning of many technical terms are intimately tied to the context they are used in. In this case 35mm refers to the size of the film you can put in a camera, where as...
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It is not clear to me that the impact of the golf ball is perpendicular to the surface of the Bowling ball. If the impact is not perpendicular then the answer answer would be 'd', not enough info.
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This is a link to a spec sheet on a par 56
http://www.chauvetlighting.com/pdfs/par56.pdf
This is either a 300 or 600 watt lamp. If you are running on 120 VAC a 10 amp circuit will run 4 300...
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Need more info.
The first is trying to get an understanding of your level of expectation. The eye is lucky to see a fluctuation that lasts under 1/30th of a second. This would imply that you could...
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First determine the rate of deceleration.
If the speed decreases by 1/2 from 21.3 mertes/second in 3 seconds, the rate of deceleration is 3.55 mertes/second. This can be verified by multiplying...
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