How much internal energy is converted to Physical Energy?
An 80kg man is standing on a 140kg pontoon boat. The system is motionless. The man dives off. His dive is perfectly horizontal (no PE change). The man goes 7 m/s to the left and the pontoon goes 4 m/s to the right. How much internal energy did the man convert to KE? The KE to the left would be 1960J and the KE to the right would be 1140J. It seems to me that the 820J difference would be dissipated energy due to friction between the boat and the water. So the total overall kinetic energy would be 1960J x 2 = 3920. Is this amount all from the internal energy of the diver? Or is it half of that because the pontoon is experiencing a reaction force? Also, if this could be counted as an explosive collision how would the formula for kinetic energy read? I thought 0 + 0 ----> 1960J + 820J + 1140J but I am not sure this is correct
Comment on ebaines's post
Okay! No, I meant to type 1120J!
Is there any dissipated energy?