A 38mL solution 0.026M solution of HCl reacts with a 0.032M NaOH.

HCl+NaOH=NaCl+H2O
number of moles of HCl originally present is 0.000988moles.

how many moles of NaOH are needed to neutralize the acid???
Please show me how to do this and , Please give me answer. Please..

I already told you how to do it. Now, do your part. Post what you think the answer is, we'll correct if required. We are not allowed to give you answers directly, but only directions, those are the forum rules, in case you didn't know.

https://www.askmehelpdesk.com/chemis...id-408452.html

b) Using your equation, you'll have the molar ratio of the reagents required. You'll see that one mole of acid reacts with one mole of alkali.

So, (0.026/1000) * 38 mol of acid will react with how many moles of alkali?

how many moles of NaOH are needed to neutralize the acid?

so, you mean answer is just 0.000988moles again??

Exactly! You see when you try?

Now for the third part, try solving it.

calculate the volume of the NaOH required to react completely with the acid

what equation needs to solve this one?

Ok, you know now you need 0.000998 mol of NaOH.

You have 0.032 mol of NaOH in 1000 mL
To have one mole, you need (1000/0.032) mL
How much volume do you need for 0.000988 mol?

Like 2 apples cost $10
1 apple cost (10/2) = $5
1/2 apple cost (10/2) * (1/2) = $2.50

It's all proportions!

So answer is 31250??

I am so sorry I just came to america few months ago.
I am not very good at english..

Thanks!

Hmmm, not quite.

You have the volume you need for 1 mole.
Try again, this time you need to find for 0.000988 mol, the amount of moles you required before.

By the way, if you aren't quite at ease with english, which language do you speak with more ease? I can do with french.

I am speaking Korean..
Could you please show me equation?
Thanks!

There is no equation for this!

You only use your logic!

Ok, I'll give another example:

5 moles of HCl are in 50 mL

How in how much volume is there 0.23 moles of HCl?

5 moles -> 50 mL
1 mole -> 50/5 = 10 mL
0.23 moles -> 10*0.23 = 2.3 mL

Now, do the same with your problem:

0.032 moles -> 1000 mL
1 mole -> 1000/0.032 = 31250 mL
0.000988 mol -> ?

31250/0.000988=3.16x10^7

like this?.

Nope. Look back at my example. How did I get the volume of HCl for 0.23 moles?

1000/0.000988=1.01x10^6

like this is correct?.

Thank you!

No again.

The answer is:

0.032 moles -> 1000 mL
1 mole -> 1000/0.032 = 31250 mL
0.000988 mol -> 31250*0.000988 = 30.875 mL

Just in case, '*' means multiplication.

Oh...
now I got it thank you so much...

So, we can conclude like it

A 38mL solution 0.026M solution of HCl reacts with a 0.032M NaOH.

a)write a balanced chemical reaction for the above process.
HCl+NaOH=NaCl+H2O

b)calculate the number of moles of HCl originally present.
(0.026moles/Liter)*(38mL/1)*(1Liter/1000mL)=0.000988moles.

c)how many moles of NaOH are needed to neutralize the acid?
(0.026/1000)*38=0.000988mloles

d)calculate the volume of the NaOH required to react completely with the acid.
31250*0.000988=30.875mL


Can you check it out for me?
Thank you sososo much

Well done! :)

Thank you
Are you a teacher?

Nope, a student. Perhaps. At a slightly higher level than you...