This is for all you calculus people...

a) Solve this both by partial fractions and integration by parts
b) Show that the answers are equivalent

http://xs22.xs.to/pics/05130/integral.GIF.xs.jpg (http://xs.to/xs.php?h=xs22&d=05130&f=integral.GIF)

If you can get this, I'll send you this gift
http://www.thewholesaledetective.com/?hop=psprpspr

Ok now, instead of the wholesale list, the new prize is the ebook David Blane's Magic Secrets Revealed.

INeedHelp505,

You do realize no one is going to answer your question because you offered as a "reward" something most people would pay you _not_ to give them...

Yeah, that's true... I don't even know how to integrate by partial fractions yet... I'm still in calc AB. I do know how to integrate by parts though, I got bored in class. Nonetheless. I'm just too lazy to answer that question.

Some times partial fractions can be easily done.

Lets get the function x^2 in terms of x+2

x^2 = [x+2-2]^2

= (x+2)^2 -4(x+2)+ 4

Then x^2 /(x+2)^3 = 1/(x+2) -4(x+2)^2 +4/(x+2)^3
by division of each term by denominator on left.

Each of these terms can be integrated.