the volume of liquid Vcm^3 at time t seconds satisfies

-15dV/dt=2V-450

given that the volume is 300cm^3 find to the nearest cm^3 the volume after 15 seconds

Work this one the same way as I showed you in the other post.
Separate variables and use V(0)=300 to find C.

OK I get to
(integrate) -15(2V-450)^-1=(integrate)dt

(=) ? =t+c

I'm not sure how to solve my left hand side (but am I on the right track so far)

Separate variables:

-15\frac{dV}{dt}=2(V-225)

\frac{dV}{V-225}=\frac{-2}{15}dt

Now, continue. Same way as other post. Let me know if you get hung up.

Give it a earnest go first, though. :)

Thanks I got it now

Thanks for the help