rab123
Apr 26, 2007, 05:38 PM
How long is the base of an isosceles triangle if the equal sides are 20 cm long and the base angles measure 52 degrees
galactus
Apr 26, 2007, 05:53 PM
40cos(52) or 40sin(38)
Do you see why?
carolinagirl_kelsey
Apr 26, 2007, 06:00 PM
If the base equals "b" and the two congruent sides equal "s":
A perpendicular bisector of the base equals "b/2" and creates two congruent right triangles.
The third angle equals 76, and with a perpendicular bisector equals 38 in one of the congruent right triangles.
-So- sin38= (b/2)/20
Solve for "b" to find length of the base.