What is the hypotenuse of an isosceles triangle if the perimeter is 16 + 16 radical 2?

The perimeter is 2a+b=16+16\sqrt{2}

The hypoteneuse is \sqrt{a^{2}+a^{2}}=\sqrt{2}a=b


2a+\sqrt{2}a=16(1+\sqrt{2})

Solve for a.

Is that the final answer or does it have to be simplified?

I said "solve for a".

Oh ok, sorry I didn't see that sentence. Thank you for your help.

You're so welcome. Few that post on this site bother to even drop a line and say thanks.

The perimeter is 2a+b=16+16\sqrt{2}

The hypoteneuse is \sqrt{a^{2}+a^{2}}=\sqrt{2}a=b


2a+\sqrt{2}a=16(1+\sqrt{2})

Solve for a.


Factor out 'a' and divide through.

a(2+\sqrt{2})=16(1+\sqrt{2})

Now, it's easy. Ain't it? Just be sure to simplify it down.

Got it. Thank you very much.

May I ask you if the answer to this is 16(1-radical2)?

Poor kid, you're sure having a time with basic algebra.

a=\frac{16(1+\sqrt{2})}{2(1+\frac{\sqrt{2}}{2})}

Practice simplfying this. Rationalize the denominator.

It reduces to 8\sqrt{2}

That's a side. Now, use that to find the length of the hypoteneuse. Should be easy.

There ya' go. ;)

Dude, relax - these people in the post are trying to get some help - no need to show off or have this rude attitude...

Dude, relax - these people in the post are trying to get some help - no need to show off or have this rude attitude...

And this thread is 3 years old :rolleyes:

Just try to have a look at the post date before posting next time. Apparently, 'reviving' threads can slow the site down.

Sorry man, just couldn't stand to write it... will look at the date first next time...
Thanks



And this thread is 3 years old :rolleyes:

Just try to have a look at the post date before posting next time. Apparently, 'reviving' threads can slow the site down.

It's all right, I didn't know either of that when I joined, and it's through mistakes that we learn, right? :D

I just wanted to point that fact out. Thank you! :)

You're truly right, learning by mistake :)

Thanks bud - glad to see there are still nice people around in this blog...

C-


It's all right, I didn't know either of that when I joined, and it's through mistakes that we learn, right? :D

I just wanted to point that fact out. Thank you! :)

How do you go from the square root of a squared plus a squared to the square root of two times a. Please respond asap if at all possible.

how do you go from the square root of a squared plus a squared to the square root of two times a. Please respond asap if at all possible.

This:

\sqrt{a^2 + a^2}

becomes this:

\sqrt{2a^2}

Which then is the same thing as:

\sqrt2 \sqrt{a^2}

and \sqrt{a^2} = a

Therefore:

\sqrt{2a^2} = \sqrt2 a