luffy
Apr 10, 2007, 08:11 PM
1/sinxcosx-cosx/sinx=tanx
galactus
Apr 11, 2007, 06:53 AM
\frac{1}{sin(x)cos(x)}-\frac{cos(x)}{sin(x)}=tan(x)
Cross multiply left side:
\frac{sin(x)-sin(x)cos^{2}(x)}{sin^{2}(x)cos(x)}
Factor out sinx:
\frac{\sout{sin(x)}(\overbrace{1-cos^{2}(x)}^{\text{sin^2(x)}})}{\sout{sin(x)}(sin( x)cos(x)}
\frac{sin^{2}(x)}{sin(x)cos(x)}=\frac{sin(x)}{cos( x)}=tan(x)